(3x-1)^2/5=7

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Solution for (3x-1)^2/5=7 equation:


x in (-oo:+oo)

((3*x-1)^2)/5 = 7 // - 7

((3*x-1)^2)/5-7 = 0

((3*x-1)^2)/5+(-7*5)/5 = 0

(3*x-1)^2-7*5 = 0

9*x^2-6*x-34 = 0

9*x^2-6*x-34 = 0

9*x^2-6*x-34 = 0

DELTA = (-6)^2-(-34*4*9)

DELTA = 1260

DELTA > 0

x = (1260^(1/2)+6)/(2*9) or x = (6-1260^(1/2))/(2*9)

x = (6*35^(1/2)+6)/18 or x = (6-6*35^(1/2))/18

(x-((6-6*35^(1/2))/18))*(x-((6*35^(1/2)+6)/18)) = 0

((x-((6-6*35^(1/2))/18))*(x-((6*35^(1/2)+6)/18)))/5 = 0

((x-((6-6*35^(1/2))/18))*(x-((6*35^(1/2)+6)/18)))/5 = 0 // * 5

(x-((6-6*35^(1/2))/18))*(x-((6*35^(1/2)+6)/18)) = 0

( x-((6*35^(1/2)+6)/18) )

x-((6*35^(1/2)+6)/18) = 0 // + (6*35^(1/2)+6)/18

x = (6*35^(1/2)+6)/18

( x-((6-6*35^(1/2))/18) )

x-((6-6*35^(1/2))/18) = 0 // + (6-6*35^(1/2))/18

x = (6-6*35^(1/2))/18

x in { (6*35^(1/2)+6)/18, (6-6*35^(1/2))/18 }

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